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A constant eastward horizontal force of 70
A constant eastward horizontal force of 70








a constant eastward horizontal force of 70

A rectangle has dimensions of 45.8cm x 21.8cm.Ī. How many significant digits are in the following measurements. List the four rules for significant digits.ġ. Calculate the area of a lab table in pencil length units.Ģ. Measure the length and width of a lab table in pencil units. Estimate the area of a lab table in pencil length units. You will use the length of a pencil as your unit. Estimate the length and width of a lab table. Calculate the area of your desk in pencil length units.Ġ90722BCDP002-1. Measure the length and width of your desk in pencil units. Estimate the area of your desk in pencil length units. Estimate the length and width of your desk. Why do you think that I would ask you these questions?Ġ90722AWUP002-1. Type in your estimates for the number of objects.Ġ90622BCDP001-What would you like to study in college? What would you like to do long term to earn a living? List activities/hobbies that you enjoy. Your parent/guardian names with their email addresses.

A CONSTANT EASTWARD HORIZONTAL FORCE OF 70 CODE

Physics Honors 5B-6AB Google class code i4tqihqĪIS Sciences 7A Google class code zhisizyĠ90622AWUP001-If you have not done so already, please email me so I can save your address! Your parents/guardians will do the same and tell them to clearly indicate who they are! Please put your name in the subject line with the class name and period. Physics Regents 1AB-2A Google class code bqejnuuĬhemistry Regents 2B-3AB Google class code zg7bquv Please Remember that this Page is the GO TO for Physics Class Information! Weight (also called the force of gravity) is a pervasive force that acts at all times and must be counteracted to keep an object from falling."Excellence is never an accident it is the result of high intention, sincere effort, intelligent direction, skillful execution, and the vision to see obstacles as opportunities." Unknown You must support the weight of a heavy object by pushing up on it when you hold it stationary, as illustrated in (Figure)(a). But how do inanimate objects like a table support the weight of a mass placed on them, such as shown in (Figure)(b)? When the bag of dog food is placed on the table, the table sags slightly under the load. This would be noticeable if the load were placed on a card table, but even a sturdy oak table deforms when a force is applied to it. Unless an object is deformed beyond its limit, it will exert a restoring force much like a deformed spring (or a trampoline or diving board). The greater the deformation, the greater the restoring force. Thus, when the load is placed on the table, the table sags until the restoring force becomes as large as the weight of the load. At this point, the net external force on the load is zero.

a constant eastward horizontal force of 70

That is the situation when the load is stationary on the table. The table sags quickly and the sag is slight, so we do not notice it.

a constant eastward horizontal force of 70

But it is similar to the sagging of a trampoline when you climb onto it. This is a two-dimensional problem, since not all forces on the skier (the system of interest) are parallel. The approach we have used in two-dimensional kinematics also works well here. Choose a convenient coordinate system and project the vectors onto its axes, creating two one-dimensional problems to solve. The most convenient coordinate system for motion on an incline is one that has one coordinate parallel to the slope and one perpendicular to the slope. (Motions along mutually perpendicular axes are independent.) We use x and y for the parallel and perpendicular directions, respectively. Is drawn parallel to the slope and downslope (it causes the motion of the skier down the slope), and Regarding the forces, friction is drawn in opposition to motion (friction always opposes forward motion) and is always parallel to the slope, This choice of axes simplifies this type of problem, because there is no motion perpendicular to the slope and the acceleration is downslope. Is drawn as the component of weight perpendicular to the slope. The magnitude of the component of weight parallel to the slope is Then, we can consider the separate problems of forces parallel to the slope and forces perpendicular to the slope. Which is the acceleration parallel to the incline when there is 45.0 N of opposing friction. Since friction always opposes motion between surfaces, the acceleration is smaller when there is friction than when there is none. It is a general result that if friction on an incline is negligible, then the acceleration down the incline is










A constant eastward horizontal force of 70